(x^-1)-(x^-2)-(5/36)=0

Solution for (x^-1)-(x^-2)-(5/36)=0 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^-1-x^-2-(5/36) = 0

x^-1-x^-2-5/36 = 0

t_1 = x^-1

1*t_1^1-1*t_1^2-5/36 = 0

t_1-t_1^2-5/36 = 0

DELTA = 1^2-(-1*(-5/36)*4)

DELTA = 4/9

DELTA > 0

t_1 = ((4/9)^(1/2)-1)/(-1*2) or t_1 = (-(4/9)^(1/2)-1)/(-1*2)

t_1 = 1/6 or t_1 = 5/6

t_1 = 1/6

x^-1-1/6 = 0

1*x^-1 = 1/6 // : 1

x^-1 = 1/6

-1 < 0

1/(x^1) = 1/6 // * x^1

1 = 1/6*x^1 // : 1/6

6 = x^1

x = 6

t_1 = 5/6

x^-1-5/6 = 0

1*x^-1 = 5/6 // : 1

x^-1 = 5/6

-1 < 0

1/(x^1) = 5/6 // * x^1

1 = 5/6*x^1 // : 5/6

6/5 = x^1

x = 6/5

x in { 6, 6/5 }